# Deducing Coulomb’s Law From Gauss’s Law

## Gauss’s Law-

Before you go through this article, make sure that you have gone through the previous article on Gauss’s Law.

We have learnt-

• Gauss’s Law helps to find the total electric flux through any closed surface.
• It states that the total electric flux through any closed surface is 1/εo times the net charge enclosed within it.

## Coulomb’s Law From Gauss’s Law-

Coulomb’s law and Gauss’s law are complementary to each other i.e. any of the two can be regarded as basic and then the other can be derived out of it.

To derive Coulomb’s law from Gauss’s law, consider two point charges Q1 and Q2 separated by a distance r as shown-

We draw a spherical Gaussian surface of radius r with O as the center and calculate the electric field intensity on it using Gauss’s law.

According to Gauss’s theorem,

Clearly,

• The angle between electric field intensity and elemental area vector over the surface at any point = 0°
• The charge enclosed by the Gaussian surface, qenc = Q1

Substituting and solving, we have-

This is the value of electric field intensity at the position of charge Q2.

Therefore, force experienced by charge Q2 is given by-

This is a mathematical form of Coulomb’s law.